Show-that-Xn-is-a-submartingale-

2.09 conclusions
March 27, 2021
dimensions-of-personality
March 27, 2021

Show-that-Xn-is-a-submartingale-

Let M0, M1, …Mn be a martingale. Show that

Xn = e^-2Mn , n= 0,1, …. , N is a submartingale.

Hint: (See Exercise 2.3 in the textbook).

 
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